An arithmetic series adds terms with a constant difference d.
Sum of first n terms
Sₙ = n/2 · (2a + (n−1)d)
Try it
Sum 1 + 2 + 3 + ... + 100
n=100, a=1, d=1. S = 100/2 · (2 + 99) = 50 · 101 = 5050.
An arithmetic series adds terms with a constant difference d.
Sum 1 + 2 + 3 + ... + 100
n=100, a=1, d=1. S = 100/2 · (2 + 99) = 50 · 101 = 5050.