A geometric series multiplies by a constant ratio r each step.
Sum of n terms
Sₙ = a(1 − rⁿ)/(1 − r)
Infinite sum (|r|<1)
S = a/(1 − r)
Try it
1 + 1/2 + 1/4 + 1/8 + ...
a=1, r=1/2. S = 1/(1−1/2) = 2.
A geometric series multiplies by a constant ratio r each step.
1 + 1/2 + 1/4 + 1/8 + ...
a=1, r=1/2. S = 1/(1−1/2) = 2.